Found problems: 49
2020 Baltic Way, 2
Let $a, b, c$ be positive real numbers such that $abc = 1$. Prove that
$$\frac{1}{a\sqrt{c^2 + 1}} + \frac{1}{b\sqrt{a^2 + 1}} + \frac{1}{c\sqrt{b^2+1}} > 2.$$
2016 Baltic Way, 16
In triangle $ABC,$ the points $D$ and $E$ are the intersections of the angular bisectors from $C$ and $B$ with the sides $AB$ and $AC,$ respectively. Points $F$ and $G$ on the extensions of $AB$ and $AC$ beyond $B$ and $C,$ respectively, satisfy $BF = CG = BC.$ Prove that $F G \parallel DE.$
2021 Baltic Way, 18
Find all integer triples $(a, b, c)$ satisfying the equation
$$
5 a^2 + 9 b^2 = 13 c^2.
$$
2017 Baltic Way, 5
Find all functions $f:\mathbb{R}\rightarrow\mathbb{R}$ such that $$f(x^2y)=f(xy)+yf(f(x)+y)$$ for all real numbers $x$ and $y$.
2018 Baltic Way, 17
Prove that for any positive integers $p,q$ such that $\sqrt{11}>\frac{p}{q}$, the following inequality holds:
\[\sqrt{11}-\frac{p}{q}>\frac{1}{2pq}.\]
2014 Contests, 3
Positive real numbers $a, b, c$ satisfy $\frac{1}{a} +\frac{1}{b} +\frac{1}{c} = 3.$ Prove the inequality \[\frac{1}{\sqrt{a^3+ b}}+\frac{1}{\sqrt{b^3 + c}}+\frac{1}{\sqrt{c^3 + a}}\leq \frac{3}{\sqrt{2}}.\]
2015 Baltic Way, 9
Let $n>2$ be an integer. A deck contains $\frac{n(n-1)}{2}$ cards,numbered \[1,2,3,\cdots , \frac{n(n-1)}{2}\] Two cards form a [i]magic pair[/i] if their numbers are consecutive , or if their numbers are $1$ and $\frac{n(n+1)}{2}$. For which $n$ is it possible to distribute the cards into $n$ stacks in such a manner that, among the cards in any two stacks , there is exactly one [i]magic pair[/i]?
2012 Baltic Way, 5
Find all functions $f : \mathbb{R} \rightarrow \mathbb{R}$ for which
\[f(x + y) = f(x - y) + f(f(1 - xy))\]
holds for all real numbers $x$ and $y$.
2019 Baltic Way, 3
Find all functions $f:\mathbb{R}\to\mathbb{R}$ such that
$$f(xf(y)-y^2)=(y+1)f(x-y)$$
holds for all $x,y\in\mathbb{R}$.
2022 Baltic Way, 4
The positive real numbers $x,y,z$ satisfy $xy+yz+zx=1$. Prove that:
$$ 2(x^2+y^2+z^2)+\frac{4}{3}\bigg (\frac{1}{x^2+1}+\frac{1}{y^2+1}+\frac{1}{z^2+1}\bigg) \ge 5 $$
2019 Baltic Way, 16
For a positive integer $N$, let $f(N)$ be the number of ordered pairs of positive integers $(a,b)$ such that the number
$$\frac{ab}{a+b}$$
is a divisor of $N$. Prove that $f(N)$ is always a perfect square.
2024 Baltic Way, 1
Let $\alpha$ be a non-zero real number. Find all functions $f: \mathbb{R}\to\mathbb{R}$ such that
\[
xf(x+y)=(x+\alpha y)f(x)+xf(y)
\]
for all $x,y\in\mathbb{R}$.
2022 Baltic Way, 13
Let $ABCD$ be a cyclic quadrilateral with $AB < BC$ and $AD < DC$. Let $E$ and $F$ be points on the sides $BC$ and $CD$, respectively, such that $AB = BE$ and $AD = DF$. Let further M denote the midpoint of the segment $EF$. Prove that $\angle BMD = 90^o$.
2017 Baltic Way, 14
Let $P$ be a point inside the acute angle $\angle BAC$. Suppose that $\angle ABP = \angle ACP = 90^{\circ}$. The points $D$ and $E$ are on the segments $BA$ and $CA$, respectively, such that $BD = BP$ and $CP = CE$. The points $F$ and $G$ are on the segments $AC$ and $AB$, respectively, such that $DF$ is perpendicular to $AB$ and $EG$ is perpendicular to $AC$. Show that $PF = PG$.
2019 Baltic Way, 1
For all non-negative real numbers $x,y,z$ with $x \geq y$, prove the inequality
$$\frac{x^3-y^3+z^3+1}{6}\geq (x-y)\sqrt{xyz}.$$
2022 Baltic Way, 5
Let $\mathbb{R}$ be the set of real numbers. Determine all functions $f: \mathbb{R} \rightarrow \mathbb{R}$ such that $f(0)+1=f(1)$ and for any real numbers $x$ and $y$,
$$ f(xy-x)+f(x+f(y))=yf(x)+3 $$
2022 Baltic Way, 12
An acute-angled triangle $ABC$ has altitudes $AD, BE$ and $CF$. Let $Q$ be an interior point of the segment $AD$, and let the circumcircles of the triangles $QDF$ and $QDE$ meet the line $BC$ again at points $X$ and $Y$ , respectively. Prove that $BX = CY$ .
2013 Baltic Way, 4
Prove that the following inequality holds for all positive real numbers $x,y,z$:
\[\dfrac{x^3}{y^2+z^2}+\dfrac{y^3}{z^2+x^2}+\dfrac{z^3}{x^2+y^2}\ge \dfrac{x+y+z}{2}.\]
2024 Baltic Way, 12
Let $ABC$ be an acute triangle with circumcircle $\omega$ such that $AB<AC$. Let $M$ be the midpoint of the arc $BC$ of~$\omega$ containing the point~$A$, and let $X\neq M$ be the other point on $\omega$ such that $AX=AM$. Points $E$ and $F$ are chosen on sides $AC$ and $AB$ of the triangle $ABC$ such that $EX=EC$ and $FX=FB$. Prove that $AE=AF$.
2005 Baltic Way, 7
A rectangular array has $ n$ rows and $ 6$ columns, where $ n \geq 2$. In each cell there is written either $ 0$ or $ 1$. All rows in the array are different from each other. For each two rows $ (x_{1},x_{2},x_{3},x_{4},x_{5},x_{6})$ and $ (y_{1},y_{2},y_{3},y_{4},y_{5},y_{6})$, the row $ (x_{1}y_{1},x_{2}y_{2},x_{3}y_{3},x_{4}y_{4},x_{5}y_{5},x_{6}y_{6})$ can be found in the array as well. Prove that there is a column in which at least half of the entries are zeros.
2014 Contests, 4
Find all functions $f$ defined on all real numbers and taking real values such that \[f(f(y)) + f(x - y) = f(xf(y) - x),\] for all real numbers $x, y.$
2018 Baltic Way, 8
A graph has $N$ vertices. An invisible hare sits in one of the vertices. A group of hunters tries to kill the hare. In each move all of them shoot simultaneously: each hunter shoots at a single vertex, they choose the target vertices cooperatively. If the hare was in one of the target vertices during a shoot, the hunt is finished. Otherwise the hare can stay in its vertex or jump to one of the neighboring vertices.
The hunters know an algorithm that allows them to kill the hare in at most $N!$ moves. Prove that then there exists an algorithm that allows them to kill the hare in at most $2^N$ moves.
2020 Baltic Way, 13
Let $ABC$ be an acute triangle with circumcircle $\omega$. Let $\ell$ be the tangent line to $\omega$ at $A$. Let $X$ and $Y$ be the projections of $B$ onto lines $\ell$ and $AC$, respectively. Let $H$ be the orthocenter of $BXY$. Let $CH$ intersect $\ell$ at $D$. Prove that $BA$ bisects angle $CBD$.
2020 Baltic Way, 1
Let $a_0>0$ be a real number, and let
$$a_n=\frac{a_{n-1}}{\sqrt{1+2020\cdot a_{n-1}^2}}, \quad \textrm{for } n=1,2,\ldots ,2020.$$
Show that $a_{2020}<\frac1{2020}$.