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Found problems: 1

2014 Bosnia and Herzegovina Junior BMO TST, 2
Tags: geometry , Right Angled , Triangle
In triangle $ABC$, on line $CA$ it is given point $D$ such that $CD = 3 \cdot CA$ (point $A$ is between points $C$ and $D$), and on line $BC$ it is given point $E$ ($E \neq B$) such that $CE=BC$. If $BD=AE$, prove that $\angle BAC= 90^{\circ}$