Olympiad problems

2010 Laurențiu Panaitopol, Tulcea, 1

Let be two real numbers $ a<b $ and a function $ f:[a,b]\longrightarrow\mathbb{R} $ having the property that if the sequence $ \left(f\left( x_n \right)\right)_{n\ge 1} $ is convergent, then the sequence $ \left( x_n \right)_{n\ge 1} $ is convergent. [b]a)[/b] Prove that if $ f $ admits antiderivatives, then $ f $ is integrable. [b]b)[/b] Is the converse of [b]a)[/b] true? [i]Marcelina Popa[/i]

indefinite integral function primitivableness integral real analysis differentiability antiderivative algebra sequences

1985 Traian Lălescu, 1.2

Is there a real interval $ I $ for which there exists a primitivable function $ f:I\longrightarrow I $ with the property that $ (f\circ f) (x)=-x, $ for all $ x\in I $ ?

calculus function primitivableness real analysis antiderivative algebra

2010 Laurențiu Panaitopol, Tulcea, 2

Let be a real number $ c $ and a differentiable function $ f:\mathbb{R}\longrightarrow\mathbb{R} $ such that $$ f(c)\neq \frac{1}{b-a}\int_a^b f(x)dx, $$ for any real numbers $ a\neq b. $ Prove that $ f'(c)=0. $ [i]Florin Rotaru[/i]

function primitivableness real analysis integration Cauchy-Schwarz inequality algebra calculus