Found problems: 85335
2023 Assara - South Russian Girl's MO, 2
The natural numbers $a$ and $b$ are such that $a^a$ is divisible by $b^b$. Can we say that then $a$ is divisible by $b$?
2019 Durer Math Competition Finals, 2
Prove that if a triangle has integral side lengths and its circumradius is a prime number then the triangle is right-angled.
1990 IMO Longlists, 34
There are $n$ non-coplanar points in space. Prove that there exists a circle exactly passes through three points of them.
2020 IMO Shortlist, G8
Let $ABC$ be a triangle with incenter $I$ and circumcircle $\Gamma$. Circles $\omega_{B}$ passing through $B$ and $\omega_{C}$ passing through $C$ are tangent at $I$. Let $\omega_{B}$ meet minor arc $AB$ of $\Gamma$ at $P$ and $AB$ at $M\neq B$, and let $\omega_{C}$ meet minor arc $AC$ of $\Gamma$ at $Q$ and $AC$ at $N\neq C$. Rays $PM$ and $QN$ meet at $X$. Let $Y$ be a point such that $YB$ is tangent to $\omega_{B}$ and $YC$ is tangent to $\omega_{C}$.
Show that $A,X,Y$ are collinear.
2023 Yasinsky Geometry Olympiad, 4
The circle inscribed in triangle $ABC$ touches $AC$ at point $F$. The perpendicular from point $F$ on $BC$ intersects the bisector of angle $C$ at point $N$. Prove that segment $FN$ is equal to the radius of the circle inscribed in triangle $ABC$.
(Oleksii Karliuchenko)
2011 Finnish National High School Mathematics Competition, 5
Two players, the builder and the destroyer, plays the following game. Builder starts and players chooses alternatively different elements from the set $\{0,1,\ldots,10\}.$ Builder wins if some four integer of those six integer he chose forms an arithmetic sequence. Destroyer wins if he can prevent to form such an arithmetic four-tuple. Which one has a winning strategy?
2021 2nd Memorial "Aleksandar Blazhevski-Cane", 4
Find all positive integers $n$ that have precisely $\sqrt{n+1}$ natural divisors.
2023 Taiwan TST Round 2, A
For each positive integer $k$ greater than $1$, find the largest real number $t$ such that the following hold:
Given $n$ distinct points $a^{(1)}=(a^{(1)}_1,\ldots, a^{(1)}_k)$, $\ldots$, $a^{(n)}=(a^{(n)}_1,\ldots, a^{(n)}_k)$ in $\mathbb{R}^k$, we define the score of the tuple $a^{(i)}$ as
\[\prod_{j=1}^{k}\#\{1\leq i'\leq n\textup{ such that }\pi_j(a^{(i')})=\pi_j(a^{(i)})\}\]
where $\#S$ is the number of elements in set $S$, and $\pi_j$ is the projection $\mathbb{R}^k\to \mathbb{R}^{k-1}$ omitting the $j$-th coordinate. Then the $t$-th power mean of the scores of all $a^{(i)}$'s is at most $n$.
Note: The $t$-th power mean of positive real numbers $x_1,\ldots,x_n$ is defined as
\[\left(\frac{x_1^t+\cdots+x_n^t}{n}\right)^{1/t}\]
when $t\neq 0$, and it is $\sqrt[n]{x_1\cdots x_n}$ when $t=0$.
[i]Proposed by Cheng-Ying Chang and usjl[/i]
2001 National Olympiad First Round, 23
Which of the followings is false for the sequence $9,99,999,\dots$?
$\textbf{(A)}$ The primes which do not divide any term of the sequence are finite.
$\textbf{(B)}$ Infinitely many primes divide infinitely many terms of the sequence.
$\textbf{(C)}$ For every positive integer $n$, there is a term which is divisible by at least $n$ distinct prime numbers.
$\textbf{(D)}$ There is an inteter $n$ such that every prime number greater than $n$ divides infinitely many terms of the sequence.
$\textbf{(E)}$ None of above
2019-2020 Winter SDPC, 8
Let $ABC$ be a triangle with circumcircle $\Gamma$. If the internal angle bisector of $\angle A$ meets $BC$ and $\Gamma$ at $D$ and $E$ respectively. Let $O_1$ be the center of the circle through $A$ and $D$ tangent to $BC$, let the external angle bisector of $\angle A$ meet $\Gamma$ at $F$, and let $FO_1$ meet $\Gamma$ at some point $P \neq F$. Show that the circumcircle of $DEP$ is tangent to $BC$.
1964 All Russian Mathematical Olympiad, 044
Given an arbitrary set of $2k+1$ integers $\{a_1,a_2,...,a_{2k+1}\}$. We make a new set $$ \{(a_1+a_2)/2, (a_2+a_3)/2, (a_{2k}+a_{2k+1})/2, (a_{2k+1}+a_1)/2\}$$ and a new one, according to the same rule, and so on... Prove that if we obtain integers only, the initial set consisted of equal integers only.
1998 Polish MO Finals, 1
Find all solutions in positive integers to:
\begin{eqnarray*} a + b + c = xyz \\ x + y + z = abc \end{eqnarray*}
2018 Morocco TST., 1
Let $a_1,a_2,\ldots a_n,k$, and $M$ be positive integers such that
$$\frac{1}{a_1}+\frac{1}{a_2}+\cdots+\frac{1}{a_n}=k\quad\text{and}\quad a_1a_2\cdots a_n=M.$$
If $M>1$, prove that the polynomial
$$P(x)=M(x+1)^k-(x+a_1)(x+a_2)\cdots (x+a_n)$$
has no positive roots.
2007 Harvard-MIT Mathematics Tournament, 36
[i]The Marathon.[/i] Let $\omega$ denote the incircle of triangle $ABC$. The segments $BC$, $CA$, and $AB$ are tangent to $\omega$ at $D$, $E$ and $F$, respectively. Point $P$ lies on $EF$ such that segment $PD$ is perpendicular to $BC$. The line $AP$ intersects $BC$ at $Q$. The circles $\omega_1$ and $\omega_2$ pass through $B$ and $C$, respectively, and are tangent to $AQ$ at $Q$; the former meets $AB$ again at $X$, and the latter meets $AC$ again at $Y$. The line $XY$ intersects $BC$ at $Z$. Given that $AB=15$, $BC=14$, and $CA=13$, find $\lfloor XZ\cdot YZ\rfloor$.
2021 Brazil EGMO TST, 1
Let $x_0,x_1,x_2,\dots$ be a infinite sequence of real numbers, such that the following three equalities are true:
I- $x_{2k}=(4x_{2k-1}-x_{2k-2})^2$, for $k\geq 1$
II- $x_{2k+1}=|\frac{x_{2k}}{4}-k^2|$, for $k\geq 0$
III- $x_0=1$
a) Determine the value of $x_{2022}$
b) Prove that there are infinite many positive integers $k$, such that $2021|x_{2k+1}$
2017 Pan African, Problem 5
The numbers from $1$ to $2017$ are written on a board. Deka and Farid play the following game :
each of them, on his turn, erases one of the numbers. Anyone who erases a multiple of $2, 3$ or $5$ loses and the game is over. Is there a winning strategy for Deka ?
2021 Poland - Second Round, 3
Positive integers $a,b,z$ satisfy the equation $ab=z^2+1$. Prove that there exist positive integers $x,y$ such that
$$\frac{a}{b}=\frac{x^2+1}{y^2+1}$$
1996 Romania National Olympiad, 1
Let $I \subset \mathbb{R}$ be a nondegenerate interval and $f:I \to \mathbb{R}$ a differentiable function. We denote $J= \left\{ \frac{f(b)-f(a)}{b-a} : a,b \in I, a<b \right\}.$ Prove that:
$a)$ $J$ is an interval;
$b)$ $J \subset f'(I),$ and the set $f'(I) \setminus J$ contains at most two elements;
$c)$ Using parts $a)$ and $b),$ deduce that $f'$ has the intermediate value property.
2006 Harvard-MIT Mathematics Tournament, 2
Suppose $ABC$ is a scalene right triangle, and $P$ is the point on hypotenuse $\overline{AC}$ such that $\angle ABP=45^\circ$. Given that $AP=1$ and $CP=2$, compute the area of $ABC$.
2009 ELMO Problems, 4
Let $n$ be a positive integer. Given $n^2$ points in a unit square, prove that there exists a broken line of length $2n + 1$ that passes through all the points.
[i]Allen Yuan[/i]
2006 MOP Homework, 5
Let $\{a_n\}^{\inf}_{n=1}$ and $\{b_n\}^{\inf}_{n=1}$ be two sequences of real numbers such that $a_{n+1}=2b_n-a_n$ and $b_{n+1}=2a_n-b_n$ for every positive integer $n$. Prove that $a_n>0$ for all $n$, then $a_1=b_1$.
2021-IMOC, N9
Find all pairs of positive integers $(a,b)$ such that there exists a finite set $S$ satisfying that any positive integer can be written in the form $$n = x^a + y^b + s$$where $x,y$ are nonnegative integers and $s \in S$
[i]CSJL[/i]
1963 AMC 12/AHSME, 19
In counting $n$ colored balls, some red and some black, it was found that $49$ of the first $50$ counted were red. Thereafter, $7$ out of every $8$ counted were red. If, in all, $90\%$ or more of the balls counted were red, the maximum value of $n$ is:
$\textbf{(A)}\ 225 \qquad
\textbf{(B)}\ 210 \qquad
\textbf{(C)}\ 200 \qquad
\textbf{(D)}\ 180 \qquad
\textbf{(E)}\ 175$
1991 Arnold's Trivium, 3
Find the critical values and critical points of the mapping $z\mapsto z^2+2\overline{z}$ (sketch the answer).
2005 AMC 10, 10
In $ \triangle ABC$, we have $ AC \equal{} BC \equal{} 7$ and $ AB \equal{} 2$. Suppose that $ D$ is a point on line $ AB$ such that $ B$ lies between $ A$ and $ D$ and $ CD \equal{} 8$. What is $ BD$?
$ \textbf{(A)}\ 3\qquad
\textbf{(B)}\ 2 \sqrt {3}\qquad
\textbf{(C)}\ 4\qquad
\textbf{(D)}\ 5\qquad
\textbf{(E)}\ 4 \sqrt {2}$