Olympiad problems

2019 Iranian Geometry Olympiad, 5

For a convex polygon (i.e. all angles less than $180^\circ$) call a diagonal [i]bisector[/i] if its bisects both area and perimeter of the polygon. What is the maximum number of bisector diagonals for a convex pentagon? [i]Proposed by Morteza Saghafian[/i]

2019 Iranian Geometry Olympiad, 3

Tags: IGO , Iran , geometry , combinatorics

There are $n>2$ lines on the plane in general position; Meaning any two of them meet, but no three are concurrent. All their intersection points are marked, and then all the lines are removed, but the marked points are remained. It is not known which marked point belongs to which two lines. Is it possible to know which line belongs where, and restore them all? [i]Proposed by Boris Frenkin - Russia[/i]

2022 Iran-Taiwan Friendly Math Competition, 6

Tags: function , number theory , algebra , Iran , Taiwan

Find all completely multipiclative functions $f:\mathbb{Z}\rightarrow \mathbb{Z}_{\geqslant 0}$ such that for any $a,b\in \mathbb{Z}$ and $b\neq 0$, there exist integers $q,r$ such that $$a=bq+r$$ and $$f(r)<f(b)$$ Proposed by Navid Safaei

2019 Iran Team Selection Test, 5

Tags: function , algebra , TST , Iran , Iranian TST , functional equation

Find all functions $f:\mathbb{R}\rightarrow \mathbb{R}$ such that for all $x,y\in \mathbb{R}$: $$f\left(f(x)^2-y^2\right)^2+f(2xy)^2=f\left(x^2+y^2\right)^2$$ [i]Proposed by Ali Behrouz - Mojtaba Zare Bidaki[/i]

2019 Iran Team Selection Test, 5

Tags: function , algebra , TST , Iran , Iranian TST , functional equation

Find all functions $f:\mathbb{R}\rightarrow \mathbb{R}$ such that for all $x,y\in \mathbb{R}$: $$f\left(f(x)^2-y^2\right)^2+f(2xy)^2=f\left(x^2+y^2\right)^2$$ [i]Proposed by Ali Behrouz - Mojtaba Zare Bidaki[/i]

2017 Iran Team Selection Test, 1

Tags: algebra , inequalities , Iran , Iranian TST

Let $a,b,c,d$ be positive real numbers with $a+b+c+d=2$. Prove the following inequality: $$\frac{(a+c)^{2}}{ad+bc}+\frac{(b+d)^{2}}{ac+bd}+4\geq 4\left ( \frac{a+b+1}{c+d+1}+\frac{c+d+1}{a+b+1} \right).$$ [i]Proposed by Mohammad Jafari[/i]

2014 Iran Geometry Olympiad (senior), 4:

Tags: geometry , circumcircle , reflection , Iran

A tangent line to circumcircle of acute triangle $ABC$ ($AC>AB$) at $A$ intersects with the extension of $BC$ at $P$. $O$ is the circumcenter of triangle $ABC$.Point $X$ lying on $OP$ such that $\measuredangle AXP=90^\circ$.Points $E$ and $F$ lying on $AB$ and $AC$,respectively,and they are in one side of line $OP$ such that $ \measuredangle EXP=\measuredangle ACX $ and $\measuredangle FXO=\measuredangle ABX $. $K$,$L$ are points of intersection $EF$ with circumcircle of triangle $ABC$.prove that $OP$ is tangent to circumcircle of triangle $KLX$. Author:Mehdi E'tesami Fard , Iran

2016 Iran MO (3rd Round), 2

Tags: geometry , incenter , circumcircle , angle bisector , Iran , cyclic quadrilateral

Given $\triangle ABC$ inscribed in $(O)$ an let $I$ and $I_a$ be it's incenter and $A$-excenter ,respectively. Tangent lines to $(O)$ at $C,B$ intersect the angle bisector of $A$ at $M,N$ ,respectively. Second tangent lines through $M,N$ intersect $(O)$ at $X,Y$. Prove that $XYII_a$ is cyclic.

2017 Iran MO (3rd round), 1

Tags: Iran , combinatorics

There are $100$ points on the circumference of a circle, arbitrarily labelled by $1,2,\ldots,100$. For each three points, call their triangle [b]clockwise[/b] if the increasing order of them is in clockwise order. Prove that it is impossible to have exactly $2017$ [b]clockwise[/b] triangles.

2017 Iran Team Selection Test, 3

Tags: combinatorics , Iranian TST , Iran

There are $27$ cards, each has some amount of ($1$ or $2$ or $3$) shapes (a circle, a square or a triangle) with some color (white, grey or black) on them. We call a triple of cards a [i]match[/i] such that all of them have the same amount of shapes or distinct amount of shapes, have the same shape or distinct shapes and have the same color or distinct colors. For instance, three cards shown in the figure are a [i]match[/i] be cause they have distinct amount of shapes, distinct shapes but the same color of shapes. What is the maximum number of cards that we can choose such that non of the triples make a [i]match[/i]? [i]Proposed by Amin Bahjati[/i]

2022 Iran-Taiwan Friendly Math Competition, 4

Tags: geometry , moving points , Taiwan , Iran

Given an acute triangle $ABC$, let $P$ be an arbitrary point on segment $BC$. A line passing through $P$ and perpendicular to $AC$ intersects $AB$ at $P_b$. A line passing through $P$ and perpendicular to $AB$ intersects $AC$ at $P_c$. Prove that the circumcircle of triangle $AP_bP_c$ passes through a fixed point other than $A$ when $P$ varies on segment $BC$. [i]Proposed by ltf0501[/i]

2015 Iran MO (2nd Round), 1

Tags: combinatorics , 2015 , Iran

Consider a cake in the shape of a circle. It's been divided to some inequal parts by its radii. Arash and Bahram want to eat this cake. At the very first, Arash takes one of the parts. In the next steps, they consecutively pick up a piece adjacent to another piece formerly removed. Suppose that the cake has been divided to 5 parts. Prove that Arash can choose his pieces in such a way at least half of the cake is his.

2017 Iran Team Selection Test, 1

Tags: number theory , Iran , Iranian TST

Let $n>1$ be an integer. Prove that there exists an integer $n-1 \ge m \ge \left \lfloor \frac{n}{2} \right \rfloor$ such that the following equation has integer solutions with $a_m>0:$ $$\frac{a_{m}}{m+1}+\frac{a_{m+1}}{m+2}+ \cdots + \frac{a_{n-1}}{n}=\frac{1}{\textrm{lcm}\left ( 1,2, \cdots , n \right )}$$ [i]Proposed by Navid Safaei[/i]

2018 Iran MO (2nd Round), 1

Tags: Iran , geometry

Let $P $ be the intersection of $AC $ and $BD $ in isosceles trapezoid $ABCD $ ($AB\parallel CD$ , $BC=AD $) . The circumcircle of triangle $ABP $ inersects $BC $ for the second time at $X $. Point $Y $ lies on $AX $ such that $DY\parallel BC $. Prove that $\hat {YDA} =2.\hat {YCA} $.

2017 Iran Team Selection Test, 4

Tags: Iran , Iranian TST , geometry , combinatorics

There are $6$ points on the plane such that no three of them are collinear. It's known that between every $4$ points of them, there exists a point that it's power with respect to the circle passing through the other three points is a constant value $k$.(Power of a point in the interior of a circle has a negative value.) Prove that $k=0$ and all $6$ points lie on a circle. [i]Proposed by Morteza Saghafian[/I]

2017 Iran Team Selection Test, 5

Tags: Iran , Iranian TST , polynomial , algebra

Let $\left \{ c_i \right \}_{i=0}^{\infty}$ be a sequence of non-negative real numbers with $c_{2017}>0$. A sequence of polynomials is defined as $$P_{-1}(x)=0 \ , \ P_0(x)=1 \ , \ P_{n+1}(x)=xP_n(x)+c_nP_{n-1}(x).$$ Prove that there doesn't exist any integer $n>2017$ and some real number $c$ such that $$P_{2n}(x)=P_n(x^2+c).$$ [i]Proposed by Navid Safaei[/i]

2016 Iran MO (3rd Round), 1

Tags: Iran , graph theory , Directed graphs , combinatorics , Tournament graphs

In an election, there are $1395$ candidates and some voters. Each voter, arranges all the candidates by the priority order. We form a directed graph with $1395$ vertices, an arrow is directed from $U$ to $V$ when the candidate $U$ is at a higher level of priority than $V$ in more than half of the votes. (otherwise, there's no edge between $U,V$) Is it possible to generate all complete directed graphs with $1395$ vertices?

2017 Iran Team Selection Test, 6

Tags: Iran , Iranian TST , geometry

In triangle $ABC$ let $O$ and $H$ be the circumcenter and the orthocenter. The point $P$ is the reflection of $A$ with respect to $OH$. Assume that $P$ is not on the same side of $BC$ as $A$. Points $E,F$ lie on $AB,AC$ respectively such that $BE=PC \ , CF=PB$. Let $K$ be the intersection point of $AP,OH$. Prove that $\angle EKF = 90 ^{\circ}$ [i] Proposed by Iman Maghsoudi[/i]

2017 Iran Team Selection Test, 4

Tags: Iran , Iranian TST , geometry , combinatorics

There are $6$ points on the plane such that no three of them are collinear. It's known that between every $4$ points of them, there exists a point that it's power with respect to the circle passing through the other three points is a constant value $k$.(Power of a point in the interior of a circle has a negative value.) Prove that $k=0$ and all $6$ points lie on a circle. [i]Proposed by Morteza Saghafian[/I]

2010 Iran MO (2nd Round), 5

Tags: geometry , circumcircle , trigonometry , vector , angle bisector , Iran

In triangle $ABC$ we havev $\angle A=\frac{\pi}{3}$. Construct $E$ and $F$ on continue of $AB$ and $AC$ respectively such that $BE=CF=BC$. Suppose that $EF$ meets circumcircle of $\triangle ACE$ in $K$. ($K\not \equiv E$). Prove that $K$ is on the bisector of $\angle A$.

2017 Iran MO (2nd Round), 5

Tags: combinatorics , Iran

There are five smart kids sitting around a round table. Their teacher says: "I gave a few apples to some of you, and none of you have the same amount of apple. Also each of you will know the amount of apple that the person to your left and the person to your right has." The teacher tells the total amount of apples, then asks the kids to guess the difference of the amount of apple that the two kids in front of them have. $a)$ If the total amount of apples is less than $16$, prove that at least one of the kids will guess the difference correctly. $b)$ Prove that the teacher can give the total of $16$ apples such that no one can guess the difference correctly.

2018 Iran Team Selection Test, 4

Tags: number theory , Iran , Iranian TST

We say distinct positive integers $a_1,a_2,\ldots ,a_n $ are "good" if their sum is equal to the sum of all pairwise $\gcd $'s among them. Prove that there are infinitely many $n$ s such that $n$ good numbers exist. [i]Proposed by Morteza Saghafian[/i]

2017 Iranian Geometry Olympiad, 3

Tags: IGO , Iran , geometry

In the regular pentagon $ABCDE$, the perpendicular at $C$ to $CD$ meets $AB$ at $F$. Prove that $AE+AF=BE$. [i]Proposed by Alireza Cheraghi[/i]

2019 Iranian Geometry Olympiad, 2

Tags: IGO , Iran , geometry

As shown in the figure, there are two rectangles $ABCD$ and $PQRD$ with the same area, and with parallel corresponding edges. Let points $N,$ $M$ and $T$ be the midpoints of segments $QR,$ $PC$ and $AB$, respectively. Prove that points $N,M$ and $T$ lie on the same line. [img]http://s4.picofile.com/file/8372959484/E02.png[/img] [i]Proposed by Morteza Saghafian[/i]

2019 Iranian Geometry Olympiad, 3

Tags: IGO , Iran , geometry , projective geometry , cyclic quadrilateral , 2019

Circles $\omega_1$ and $\omega_2$ have centres $O_1$ and $O_2$, respectively. These two circles intersect at points $X$ and $Y$. $AB$ is common tangent line of these two circles such that $A$ lies on $\omega_1$ and $B$ lies on $\omega_2$. Let tangents to $\omega_1$ and $\omega_2$ at $X$ intersect $O_1O_2$ at points $K$ and $L$, respectively. Suppose that line $BL$ intersects $\omega_2$ for the second time at $M$ and line $AK$ intersects $\omega_1$ for the second time at $N$. Prove that lines $AM, BN$ and $O_1O_2$ concur. [i]Proposed by Dominik Burek - Poland[/i]