Found problems: 85335
1967 Swedish Mathematical Competition, 6
The vertices of a triangle are lattice points. There are no lattice points on the sides (apart from the vertices) and $n$ lattice points inside the triangle. Show that its area is $n + \frac12$. Find the formula for the general case where there are also $m$ lattice points on the sides (apart from the vertices).
1988 Tournament Of Towns, (178) 4
Pawns are placed on an infinite chess board so that they form an infinite square net (along any row or column containing pawns ther is a pawn , three free squares , pawn , three squares, and so on , with only every fourth row and every fourth column containing pawns). Prove that it is not possible for a knight to tour every free square once and only once.
(An old problem of A . K . Tolpugo)
2016 IberoAmerican, 2
Find all positive real numbers $(x,y,z)$ such that:
$$x = \frac{1}{y^2+y-1}$$
$$y = \frac{1}{z^2+z-1}$$
$$z = \frac{1}{x^2+x-1}$$
1986 AMC 8, 16
[asy]size(250);
void bargraph(real X, real Y, real ymin, real ymax, real ystep, real tickwidth,
string yformat, Label LX, Label LY, Label[] LLX, real[] height,pen p=nullpen)
{
draw((0,0)--(0,Y),EndArrow);
draw((0,0)--(X,0),EndArrow);
label(LX,(X,0),plain.SE,fontsize(9));
label(LY,(0,Y),plain.NW,fontsize(9));
real yscale=Y/(ymax+ystep);
for(real y=ymin; y<ymax; y+=ystep)
{
draw((-tickwidth,yscale*y)--(0,yscale*y));
label(format(yformat,y),(-tickwidth,yscale*y),plain.W,fontsize(9));
}
int n=LLX.length;
real xscale=X/(2*n+2);
for(int i=0;i<n;++i)
{
real x=xscale*(2*i+1);
path P=(x,0)--(x,height[i]*yscale)--(x+xscale,height[i]*yscale)--(x+xscale,0)--cycle;
fill(P,p);
draw(P);
label(LLX[i],(x+xscale/2),plain.S,fontsize(10));
}
for(int i=0;i<n;++i) draw((0,height[i]*yscale)--(X,height[i]*yscale),dashed);
}
string yf="%#.1f";
Label[] LX={"Spring","Summer","Fall","Winter"};
for(int i=0;i<LX.length;++i) LX[i]=rotate(90)*LX[i];
real[] H={4.5,5,4,4};
bargraph(60,50,1,5.1,0.5,2,yf,"season","hamburgers (millions)",LX,H,yellow);
fill(ellipse((45,30),7,10),brown);[/asy]
A bar graph shows the number of hamburgers sold by a fast food chain each season. However, the bar indicating the number sold during the winter is covered by a smudge. If exactly $ 25 \%$ of the chain's hamburgers are sold in the fall, how many million hamburgers are sold in the winter?
\[ \textbf{(A)}\ 2.5 \qquad
\textbf{(B)}\ 3 \qquad
\textbf{(C)}\ 3.5 \qquad
\textbf{(D)}\ 4 \qquad
\textbf{(E)}\ 4.5
\]
1975 IMO, 2
Let $a_{1}, \ldots, a_{n}$ be an infinite sequence of strictly positive integers, so that $a_{k} < a_{k+1}$ for any $k.$ Prove that there exists an infinity of terms $ a_{m},$ which can be written like $a_m = x \cdot a_p + y \cdot a_q$ with $x,y$ strictly positive integers and $p \neq q.$
2022 USA TSTST, 1
Let $n$ be a positive integer. Find the smallest positive integer $k$ such that for any set $S$ of $n$ points in the interior of the unit square, there exists a set of $k$ rectangles such that the following hold:
[list=disc]
[*]The sides of each rectangle are parallel to the sides of the unit square.
[*]Each point in $S$ is [i]not[/i] in the interior of any rectangle.
[*]Each point in the interior of the unit square but [i]not[/i] in $S$ is in the interior of at least one of the $k$ rectangles
[/list]
(The interior of a polygon does not contain its boundary.)
[i]Holden Mui[/i]
2019 CCA Math Bonanza, T6
Compute $\displaystyle\sum_{n=3}^{\infty}\frac{n^2-2}{\left(n^2-1\right)\left(n^2-4\right)}$.
[i]2019 CCA Math Bonanza Team Round #6[/i]
2010 Contests, 2
Joaquim, José and João participate of the worship of triangle $ABC$. It is well known that $ABC$ is a random triangle, nothing special. According to the dogmas of the worship, when they form a triangle which is similar to $ABC$, they will get immortal. Nevertheless, there is a condition: each person must represent a vertice of the triangle. In this case, Joaquim will represent vertice $A$, José vertice $B$ and João will represent vertice $C$. Thus, they must form a triangle which is similar to $ABC$, in this order.
Suppose all three points are in the Euclidean Plane. Once they are very excited to become immortal, they act in the following way: in each instant $t$, Joaquim, for example, will move with constant velocity $v$ to the point in the same semi-plan determined by the line which connects the other two points, and which would create a triangle similar to $ABC$ in the desired order. The other participants act in the same way.
If the velocity of all of them is same, and if they initially have a finite, but sufficiently large life, determine if they can get immortal.
[i]Observation: Initially, Joaquim, José and João do not represent three collinear points in the plane[/i]
1996 AMC 8, 1
How many positive factors of $36$ are also multiples of $4$?
$\text{(A)}\ 2 \qquad \text{(B)}\ 3 \qquad \text{(C)}\ 4 \qquad \text{(D)}\ 5 \qquad \text{(E)}\ 6$
2015 District Olympiad, 1
If $ a,b,c $ represent the lengths of the sides of a triangle, prove the inequality:
$$ 3\le\sum_{\text{cyc}}\sqrt{\frac{a}{-a+b+c}} . $$
2012 AMC 8, 14
In the BIG N, a middle school football conference, each team plays every other team exactly once. If a total of 21 conference games were played during the 2012 season, how many teams were members of the BIG N conference?
$\textbf{(A)}\hspace{.05in}6 \qquad \textbf{(B)}\hspace{.05in}7 \qquad \textbf{(C)}\hspace{.05in}8 \qquad \textbf{(D)}\hspace{.05in}9 \qquad \textbf{(E)}\hspace{.05in}10 $
2005 AIME Problems, 10
Given that $O$ is a regular octahedron, that $C$ is the cube whose vertices are the centers of the faces of $O$, and that the ratio of the volume of $O$ to that of $C$ is $\frac{m}{n}$, where $m$ and $n$ are relatively prime integers, find $m+n$.
2014 Contests, 2
Let $n\geq 4$ be a positive integer.Out of $n$ people,each of two individuals play table tennis game(every game has a winner).Find the minimum value of $n$,such that for any possible outcome of the game,there always exist an ordered four people group $(a_{1},a_{2},a_{3},a_{4})$,such that the person $a_{i}$ wins against $a_{j}$ for any $1\leq i<j\leq 4$
2016 BMT Spring, 8
Evaluate the following limit
$$\lim_{x\to 0} (1 + 2x + 3x^2 + 4x^3 +...)^{1/x}$$
1987 Tournament Of Towns, (162) 6
An equilateral triangle is divided by lines, parallel to its sides, into equilateral triangles, all of the same size. One of the smaller triangles is black while the others are white. It is permitted to intersect simultaneously some small triangles with a line parallel to any side of the original triangle and to change the colour of each intersected small triangle from one colour to the other . Is it always possible to find a sequence of such operations so that the smaller triangles all become white?
2016 Iranian Geometry Olympiad, 3
In a convex qualrilateral $ABCD$, let $P$ be the intersection point of $AD$ and $BC$. Suppose that $I_1$ and $I_2$ are the incenters of triangles $PAB$ and $PDC$,respectively. Let $O$ be the circumcenter of $PAB$, and $H$ the orthocenter of $PDC$. Show that the circumcircles of triangles $AI_1B$ and $DHC$ are tangent together if and only if the circumcircles of triangles $AOB$ and $DI_2C$ are tangent together.
Proposed by Hooman Fattahimoghaddam
2005 India IMO Training Camp, 2
Prove that one can find a $n_{0} \in \mathbb{N}$ such that $\forall m \geq n_{0}$, there exist three positive integers $a$, $b$ , $c$ such that
(i) $m^3 < a < b < c < (m+1)^3$;
(ii) $abc$ is the cube of an integer.
1995 Bulgaria National Olympiad, 4
Points $A_1,B_1,C_1$ are selected on the sides $BC$,$CA$,$AB$ respectively of an equilateral triangle $ABC$ in such a way that the inradii of the triangles $C_1AB_1$, $A_1BC_1$, $B_1CA_1$ and $A_1B_1C_1$ are equal. Prove that $A_1,B_1,C_1$ are the midpoints of the corresponding sides.
2024 IFYM, Sozopol, 8
Each cell in a \( 2024 \times 2024 \) table contains the letter \( A \) or \( B \), with the number of \( A \)'s in each row being the same and the number of \( B \)'s in each column being the same. Alexandra and Boris play the following game, alternating turns, with Alexandra going first. On each turn, the player chooses a row or column and erases all the letters in it that have not yet been erased, as long as at least one letter is erased during the turn, and at the end of the turn, at least one letter remains in the table. The game ends when exactly one letter remains in the table. Alexandra wins the game if the letter is \( A \), and Boris wins if it is \( B \). What is the number of initial tables for which Alexandra has a winning strategy?
1997 Canadian Open Math Challenge, 4
Given three distinct digits a, b and c, it is possible, by choosing two digits at a time, to form six two-digit numbers. Determine all possible sets {a, b, c} for which the sum of the six two-digits numbers is 484.
2017 Saudi Arabia Pre-TST + Training Tests, 3
Let $ABCD$ be a convex quadrilateral. Ray $AD$ meets ray $BC$ at $P$. Let $O,O'$ be the circumcenters of triangles $PCD, PAB$, respectively, $H,H'$ be the orthocenters of triangles $PCD, PAB$, respectively. Prove that circumcircle of triangle $DOC$ is tangent to circumcircle of triangle $AO'B$ if and only if circumcircle of triangle $DHC$ is tangent to circumcircle of triangle $AH'B$.
2015 ASDAN Math Tournament, 20
The sequence $a_1,a_2,\dots,a_{13}$ is a geometric sequence with $a_1=a$ and common ratio $r$, where $a$ and $r$ are positive integers. Given that
$$\log_{2015}a_1+\log_{2015}a_2+\dots+\log_{2015}a_{13}=2015,$$
find the number of possible ordered pairs $(a,r)$.
2021 Oral Moscow Geometry Olympiad, 3
Circle $(O)$ and its chord $BC$ are given. Point $A$ moves on the major arc $BC$. $AL$ is the angle bisector in a triangle $ABC$. Show that the disctance from the circumcenter of triangle $AOL$ to the line $BC$ does not depend on the position of point $A$.
2010 Princeton University Math Competition, 6
Find the numerator of \[\frac{1010\overbrace{11 \ldots 11}^{2011 \text{ ones}}0101}{1100\underbrace{11 \ldots 11}_{2011\text{ ones}}0011}\] when reduced.
2018 Brazil Team Selection Test, 3
Let $n > 10$ be an odd integer. Determine the number of ways to place the numbers $1, 2, \ldots , n$ around a circle so that each number in the circle divides the sum its two neighbors.
(Two configurations such that one can be obtained from the other per rotation are to be counted only once.)