Found problems: 85335
1994 Tournament Of Towns, (432) 2
Prove that one can construct two triangles from six edges of an arbitrary tetrahedron.
(VV Proizvolov)
2016 SEEMOUS, Problem 1
SEEMOUS 2016 COMPETITION PROBLEMS
2021 Vietnam National Olympiad, 3
Let $\bigtriangleup ABC$ is not an isosceles triangle and is an acute triangle, $AD,BE,CF$ be the altitudes and $H$ is the orthocenter .Let $I$ is the circumcenter of $\bigtriangleup HEF$ and let $K,J$ is the midpoint of $BC,EF$ respectively.Let $HJ$ intersects $(I)$ again at $G$ and $GK$ intersects $(I)$ at $L\neq G$.
a) Prove that $AL$ is perpendicular to $EF$.
b) Let $AL$ intersects $EF$ at $M$, the line $IM$ intersects the circumcircle $\bigtriangleup IEF$ again at $N$, $DN$ intersects $AB,AC$ at $P$ and $Q$ respectively then prove that $PE,QF,AK$ are concurrent.
2006 South East Mathematical Olympiad, 2
In $\triangle ABC$, $\angle ABC=90^{\circ}$. Points $D,G$ lie on side $AC$. Points $E, F$ lie on segment $BD$, such that $AE \perp BD $ and $GF \perp BD$. Show that if $BE=EF$, then $\angle ABG=\angle DFC$.
2008 BAMO, 3
A triangle is constructed with the lengths of the sides chosen from the set $\{2, 3, 5, 8, 13, 21, 34, 55, 89, 144\}$. Show that this triangle must be isosceles.
(A triangle is isosceles if it has at least two sides the same length.)
2002 AMC 10, 8
Suppose July of year $ N$ has five Mondays. Which of the following must occur five times in August of year $ N$? (Note: Both months have $ 31$ days.)
$ \textbf{(A)}\ \text{Monday} \qquad
\textbf{(B)}\ \text{Tuesday} \qquad
\textbf{(C)}\ \text{Wednesday} \qquad
\textbf{(D)}\ \text{Thursday} \qquad
\textbf{(E)}\ \text{Friday}$
2014 Sharygin Geometry Olympiad, 22
Does there exist a convex polyhedron such that it has diagonals and each of them is shorter than each of its edges?
2013 Chile National Olympiad, 2
Hannibal and Clarice are still at a barbecue and there are three anticuchos left, each of which it has $10$ pieces. Of the $30$ total pieces, there are $29$ chicken and one meat, the which is at the bottom of one of the anticuchos. To decide who to stay with the piece of meat, they decide to play the following game: they alternately take out a piece of one of the anticuchos (they can take only the outer pieces) and whoever wins the game manages to remove the piece of meat. Clarice decides if she starts or Hannibal starts. What should she decide?
1990 Baltic Way, 8
It is known that for any point $P$ on the circumcircle of a triangle $ABC$, the orthogonal projections of $P$ onto $AB,BC,CA$ lie on a line, called a [i]Simson line[/i] of $P$. Show that the Simson lines of two diametrically opposite points $P_1$ and $P_2$ are perpendicular.
2017 India IMO Training Camp, 2
Define a sequence of integers $a_0=m, a_1=n$ and $a_{k+1}=4a_k-5a_{k-1}$ for all $k \ge 1$. Suppose $p>5$ is a prime with $p \equiv 1 \pmod{4}$. Prove that it is possible to choose $m,n$ such that $p \nmid a_k$ for any $k \ge 0$.
2004 Brazil Team Selection Test, Problem 2
An integer $n\ge2$ is called [i]amicable[/i] if there exists subsets $A_1,A_2,\ldots,A_n$ of the set $\{1,2,\ldots,n\}$ such that
(i) $i\notin A_i$ for any $i=1,2,\ldots,n$,
(ii) $i\in A_j$ for any $j\notin A_i$, for any $i\ne j$
(iii) $A_i\cap A_j\ne\emptyset$ for any $i,j\in\{1,2,\ldots,n\}$
(a) Prove that $7$ is amicable.
(b) Prove that $n$ is amicable if and only if $n\ge7$.
2021 Saudi Arabia BMO TST, 3
Let $a$, $b$, and $c$ be positive real numbers. Prove that $$(a^5 - a^2 +3)(b^5 - b^2 +3)(c^5 - c^2 +3)\ge (a+b+c)^3$$
1997 Tournament Of Towns, (540) 5
In a game, the first player paints a point on the plane red; the second player paints 10 uncoloured points on the plane green; then the first player paints an uncoloured point on the plane red; the second player paints 10 uncoloured points on the plane green; and so on. The first player wins if there are three red points which form an equilateral triangle. Can the second player prevent the first player from winning?
(A Kanel)
2011 NIMO Summer Contest, 13
For real $\theta_i$, $i = 1, 2, \dots, 2011$, where $\theta_1 = \theta_{2012}$, find the maximum value of the expression
\[
\sum_{i=1}^{2011} \sin^{2012} \theta_i \cos^{2012} \theta_{i+1}.
\]
[i]Proposed by Lewis Chen
[/i]
2021 Baltic Way, 5
Let $x,y\in\mathbb{R}$ be such that $x = y(3-y)^2$ and $y = x(3-x)^2$. Find all possible values of $x+y$.
2009 Princeton University Math Competition, 5
A polygon is called concave if it has at least one angle strictly greater than $180^{\circ}$. What is the maximum number of symmetries that an 11-sided concave polygon can have? (A [i]symmetry[/i] of a polygon is a way to rotate or reflect the plane that leaves the polygon unchanged.)
2020 Taiwan TST Round 3, 2
On a flat plane in Camelot, King Arthur builds a labyrinth $\mathfrak{L}$ consisting of $n$ walls, each of which is an infinite straight line. No two walls are parallel, and no three walls have a common point. Merlin then paints one side of each wall entirely red and the other side entirely blue.
At the intersection of two walls there are four corners: two diagonally opposite corners where a red side and a blue side meet, one corner where two red sides meet, and one corner where two blue sides meet. At each such intersection, there is a two-way door connecting the two diagonally opposite corners at which sides of different colours meet.
After Merlin paints the walls, Morgana then places some knights in the labyrinth. The knights can walk through doors, but cannot walk through walls.
Let $k(\mathfrak{L})$ be the largest number $k$ such that, no matter how Merlin paints the labyrinth $\mathfrak{L},$ Morgana can always place at least $k$ knights such that no two of them can ever meet. For each $n,$ what are all possible values for $k(\mathfrak{L}),$ where $\mathfrak{L}$ is a labyrinth with $n$ walls?
1991 All Soviet Union Mathematical Olympiad, 541
An investigator works out that he needs to ask at most $91$ questions on the basis that all the answers will be yes or no and all will be true. The questions may depend upon the earlier answers. Show that he can make do with $105$ questions if at most one answer could be a lie.
2005 China Girls Math Olympiad, 8
Given an $ a \times b$ rectangle with $ a > b > 0,$ determine the minimum side of a square that covers the rectangle. (A square covers the rectangle if each point in the rectangle lies inside the square.)
2004 Bundeswettbewerb Mathematik, 4
A cube is decomposed in a finite number of rectangular parallelepipeds such that the volume of the cube's circum sphere volume equals the sum of the volumes of all parallelepipeds' circum spheres. Prove that all these parallelepipeds are cubes.
2017 Saudi Arabia BMO TST, 1
Let $a, b, c$ be positive real numbers. Prove that
$$\frac{a(b^2 + c^2)}{(b + c)(a^2 + bc)} + \frac{b(c^2 + a^2)}{(c + a)(b^2 + ca)} + \frac{c(a^2 + b^2)}{(a + b)(c^2 + ab)} \ge \frac32$$
2014 Harvard-MIT Mathematics Tournament, 6
We have a calculator with two buttons that displays and integer $x$. Pressing the first button replaces $x$ by $\lfloor \frac{x}{2} \rfloor$, and pressing the second button replaces $x$ by $4x+1$. Initially, the calculator displays $0$. How many integers less than or equal to $2014$ can be achieved through a sequence of arbitrary button presses? (It is permitted for the number displayed to exceed 2014 during the sequence. Here, $\lfloor y \rfloor$ denotes the greatest integer less than or equal to the real number $y$).
2017 Greece Team Selection Test, 2
Prove that the number $A=\frac{(4n)!}{(2n)!n!}$ is an integer and divisible by $2^{n+1}$,
where $n$ is a positive integer.
2000 Moldova National Olympiad, Problem 7
A triangle whose all sides have lengths greater than $1$ is contained in a unit square. Show that the center of the square lies inside the triangle.
2000 National Olympiad First Round, 29
One of the external common tangent lines of the two externally tangent circles with center $O_1$ and $O_2$ touches the circles at $B$ and $C$, respectively. Let $A$ be the common point of the circles. The line $BA$ meets the circle with center $O_2$ at $A$ and $D$. If $|BA|=5$ and $|AD|=4$, then what is $|CD|$?
$ \textbf{(A)}\ \sqrt{20}
\qquad\textbf{(B)}\ \sqrt{27}
\qquad\textbf{(C)}\ 6
\qquad\textbf{(D)}\ \frac{15}2
\qquad\textbf{(E)}\ 4\sqrt5
$